Ohm’s Law: Resistance and Simple Circuits
By the end of this section, you will be able to:
What drives current? We can think of various devices—such as batteries, generators, wall outlets, and so on—which are necessary to maintain a current. All such devices create a potential difference and are loosely referred to as voltage sources. When a voltage source is connected to a conductor, it applies a potential difference \(V\) that creates an electric field. The electric field in turn exerts force on charges, causing current.
The current that flows through most substances is directly proportional to the voltage \(V\) applied to it. The German physicist Georg Simon Ohm (1787–1854) was the first to demonstrate experimentally that the current in a metal wire is directly proportional to the voltage applied:
This important relationship is known as Ohm's law. It can be viewed as a cause-and-effect relationship, with voltage the cause and current the effect. This is an empirical law like that for friction—an experimentally observed phenomenon. Such a linear relationship doesn't always occur.
If voltage drives current, what impedes it? The electric property that impedes current (crudely similar to friction and air resistance) is called resistance \(R\). Collisions of moving charges with atoms and molecules in a substance transfer energy to the substance and limit current. Resistance is defined as inversely proportional to current, or
Thus, for example, current is cut in half if resistance doubles. Combining the relationships of current to voltage and current to resistance gives
This relationship is also called Ohm's law. Ohm's law in this form really defines resistance for certain materials. Ohm's law (like Hooke's law) is not universally valid. The many substances for which Ohm's law holds are called ohmic. These include good conductors like copper and aluminum, and some poor conductors under certain circumstances. Ohmic materials have a resistance \(R\) that is independent of voltage \(V\) and current \(I\). An object that has simple resistance is called a resistor, even if its resistance is small. The unit for resistance is an ohm and is given the symbol \(\Omega\) (upper case Greek omega). Rearranging \(I = V/R\) gives \(R = V/I\), and so the units of resistance are 1 ohm = 1 volt per ampere:
Figure 1 shows the schematic for a simple circuit. A simple circuit has a single voltage source and a single resistor. The wires connecting the voltage source to the resistor can be assumed to have negligible resistance, or their resistance can be included in \(R\).
Figure 1 A simple electric circuit in which a closed path for current to flow is supplied by conductors (usually metal wires) connecting a load to the terminals of a battery, represented by the red parallel lines. The zigzag symbol represents the single resistor and includes any resistance in the connections to the voltage source.
Ohm's law \((V = IR)\) is a fundamental relationship that could be presented by a linear function with the slope of the line being the resistance. The resistance represents the voltage that needs to be applied to the resistor to create a current of 1 A through the circuit. The graph (in the figure below) shows this representation for two simple circuits with resistors that have different resistances and thus different slopes.
The materials which follow Ohm's law by having a linear relationship between voltage and current are known as ohmic materials. On the other hand, some materials exhibit a nonlinear voltage-current relationship and hence are known as non-ohmic materials. The figure below shows current voltage relationships for the two types of materials.
Clearly the resistance of an ohmic material (shown in (a)) remains constant and can be calculated by finding the slope of the graph but that is not true for a non-ohmic material (shown in (b)).
What is the resistance of an automobile headlight through which 2.50 A flows when 12.0 V is applied to it?
Strategy
We can rearrange Ohm's law as stated by \(I = V/R\) and use it to find the resistance.
Solution
Rearranging \(I = V/R\) and substituting known values gives
Discussion
This is a relatively small resistance, but it is larger than the cold resistance of the headlight. As we shall see in Resistance and Resistivity, resistance usually increases with temperature, and so the bulb has a lower resistance when it is first switched on and will draw considerably more current during its brief warm-up period.
Resistances range over many orders of magnitude. Some ceramic insulators, such as those used to support power lines, have resistances of \(10^{12} \thinspace \Omega\) or more. A dry person may have a hand-to-foot resistance of \(10^{5} \thinspace \Omega\), whereas the resistance of the human heart is about \(10^{3} \thinspace \Omega\). A meter-long piece of large-diameter copper wire may have a resistance of \(10^{-5} \thinspace \Omega\), and superconductors have no resistance at all (they are non-ohmic). Resistance is related to the shape of an object and the material of which it is composed, as will be seen in Resistance and Resistivity.
Additional insight is gained by solving \(I = V/R\) for \(V\) yielding
This expression for \(V\) can be interpreted as the voltage drop across a resistor produced by the current \(I \). The phrase \(IR\) drop is often used for this voltage. For instance, the headlight in Example 1 has an \(IR\) drop of 12.0 V. If voltage is measured at various points in a circuit, it will be seen to increase at the voltage source and decrease at the resistor. Voltage is similar to fluid pressure. The voltage source is like a pump, creating a pressure difference, causing current—the flow of charge. The resistor is like a pipe that reduces pressure and limits flow because of its resistance. Conservation of energy has important consequences here. The voltage source supplies energy (causing an electric field and a current), and the resistor converts it to another form (such as thermal energy). In a simple circuit (one with a single simple resistor), the voltage supplied by the source equals the voltage drop across the resistor, since \(\mathrm{PE} =q \Delta V\), and the same \(q\) flows through each. Thus the energy supplied by the voltage source and the energy converted by the resistor are equal. (See Example 1.)
Figure 4 The voltage drop across a resistor in a simple circuit equals the voltage output of the battery.
In a simple electrical circuit, the sole resistor converts energy supplied by the source into another form. Conservation of energy is evidenced here by the fact that all of the energy supplied by the source is converted to another form by the resistor alone. We will find that conservation of energy has other important applications in circuits and is a powerful tool in circuit analysis.
See how the equation form of Ohm's law relates to a simple circuit. Adjust the voltage and resistance, and see the current change according to Ohm's law. The sizes of the symbols in the equation change to match the circuit diagram.
Click here to view the simulation page
What was the significant contribution of Georg Simon Ohm in the field of electricity?
If the voltage across a fixed resistance is doubled, what happens to the current?
Given an amount of voltage and resistance, what would be the effect to the electric current in a circuit if there is twice the voltage?
Given an amount of voltage and resistance, what would be the effect on the electric current in a circuit if the resistance is doubled?
What will happen to the electric current when we increase the voltage?
The current flowing on a circuit is inversely proportional to the resistance and directly proportional to the voltage. This is written in equation as
The unit for resistance is named after whose German physicist and mathematician?
A light bulb is connected to a 6-V battery. If a current of 0.3 A passes through it, what is the resistance of the filament?
\(\Omega\)
\(R={V \over I}\)
\(R={6\;V \over 0.3\;A}\)
Answer: \(20\;\Omega\)
An electric load is connected to a 84-V source. Compute for the resistance if the current that flows on the load is 29 A?
\(R={84\;V \over 29\;A}\)
Answer: \(2.8966\;\Omega\)
An electric circuit is made up of 481-\(\Omega\) resistor connected to a 10-V battery. How much current flows through the circuit?
\(A\)
\(I={10\;V \over 481\;\Omega}\)
Answer: \(0.0208\;A\)
Into what amount of electric potential does a 16-\(\Omega\) resistor should be connected to have a current of 18 A?
\(V\)
\(V=(18\;A)(16\;\Omega)\)
Answer: \(288\;V\)
A conductor with a resistance of 7 \(\Omega\) is connected to a battery of 12 V. Calculate the current flowing through the conductor.
\(I={V\over R}\)
\(I={12 \; V\over 7 \; \Omega}\)
Answer: \(1.7143 \; A\)
A conductor with a resistance of 5 \(\Omega\) is connected to a battery. The current flowing through the conductor is 15 A. Calculate the voltage between the terminals of the conductor.
\(V=(5 \; \Omega)(15 \; A)\)
Answer: \(75 \; V\)
A conductor is connected between the terminals of a 14 V battery. The current that circulates through it is 1.2 A. Calculate the resistance of the conductor.
\(R={14 \; V \over 1.2 \; A}\)
Answer: \(11.6667 \; \Omega\)
An electric heater consumes 8 A when is connected to a 111 V source. Calculate its resistance.
\(R={V\over I}\)
\(R={111\; V\over 8\;A}\)
Answer: \(13.875\;\Omega\)
Find the current that flows through an electric device with a resistance of 39 \(\Omega\) and is connected to an electric source of 119 V.
\(I={119\;V\over 39\;\Omega}\)
Answer: \(3.0513\; A\)
Which of the following statements are correct about the relationship between the voltage and the electric current according to the Ohm's law?
Choose 2 correct answers.
Calculate the voltage in the terminals of an electric device that has a resistance of 32 \(\Omega\) and consumes 6 A from the electric source.
\(V=IR\)
\(V=(6\;A)(32\;\Omega)\)
Answer: \(192\;V\)